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Properties of the Number 90440

Ninety Thousand Four Hundred Forty

Basics

Value: 90439 → 90440 → 90441

Parity: even

Prime: No

Previous Prime: 90439

Next Prime: 90469

Digit Sum: 17

Digital Root: 8

Palindrome: No

Factorization: 2 3 × 5 × 7 × 17 × 19

Divisors: 1, 2, 4, 5, 7, 8, 10, 14, 17, 19

Polygonal

Triangular: No

Square: No

Pentagonal: No

Hexagonal: No

Heptagonal: No

Tetrahedral: No

Today's Target

2196 Try Today's Challenge

Representations

Binary: 10110000101001000

Octal: 260510

Duodecimal: 44408

Hexadecimal: 16148

Square: 8179393600

Square Root: 300.7324392213118

Classification

Fibonacci: No

Bell Number: No

Factorial Number: No

Regular Number: No

Perfect Number: No

Special

Kaprekar Constant: No

Munchausen Constant: No

Armstrong Number: No

Kaprekar Number: No

Catalan Number: No

Vampire Number: No

Taxicab Number: No

Super Prime: No

Friedman Number: No

Fermat Number: No

Cullen Number: No

OEIS Sequences

Fourth convolution of Catalan numbers: a(n) = 4·binomial(2·n+3,n)/(n+4). A2057
This table shows the coefficients of sum formulas of n-th Fibonacci numbers (A000045). The k-th row (k>=1) contains T(i,k) for i=1 to k, where k=[2·n+1+(-1)n-1]/4 and T(i,k) satisfies F(n)= ∑i=1..k T(i,k) * nk-i/(k-1)!. A99731
T(n,k)=Number of length (n+k)X1 arrays of occupancy after each element moves up to +-k places including 0. A222345
An inverse Chebyshev transform of x3. A99376
a(n) = -4·binomial(2·n-5, n-4)/n for n > 0 and a(0) = 1. A115143
Table (read by rows) giving the coefficients of sum formulas of n-th Factorials (A000142). The k-th row (k>=1, n>=2) contains T(i,k) for i=1 to k+1, where k=[2·n+1+(-1)n-1]/4 and T(i,k) satisfies Fact(n) = ∑i=1..k+1 T(i,k) * (n-1)k-i+1 / (2·k-2)!. A101751
a(n) = Fibonacci(n)*A109064(n) for n>=1 with a(0)=1. A205882
Square table where T(n,k) = binomial(n*(n+k), k) * n/(n+k), for n>=1, k>=0, as read by antidiagonals. A299427
Even triangle n!. This table read by rows gives the coefficients of sum formulas of n-th factorials (A000142). The k-th row (6>=k>=1) contains T(i,k) for i=1 to k+3, where k=[2·n+1+(-1)n-1]/4 and T(i,k) satisfies n! = ∑i=1..k+3 T(i,k) * ni-1 / (2·k-2)!. A102409
Row maximum of Catalan triangle with zeros (A053121), i.e., maximum value of (m+1)*binomial(n+1,(n-m)/2)/(n+1) for given n with m same parity as n. A101461