Properties of the Number 57769

Fifty-Seven Thousand Seven Hundred Sixty-Nine

Basics

Value: 57768 → 57769 → 57770

Parity: odd

Prime: No

Previous Prime: 57751

Next Prime: 57773

Digit Sum: 34

Digital Root: 7

Palindrome: No

Factorization: 41 × 1409

Divisors: 1, 41, 1409, 57769

Polygonal

Triangular: No

Square: No

Pentagonal: No

Hexagonal: No

Heptagonal: No

Tetrahedral: No

Today's Target

2196 Try Today's Challenge

Representations

Binary: 1110000110101001

Octal: 160651

Duodecimal: 29521

Hexadecimal: e1a9

Square: 3337257361

Square Root: 240.3518254559345

Classification

Fibonacci: No

Bell Number: No

Factorial Number: No

Regular Number: No

Perfect Number: No

Special

Kaprekar Constant: No

Munchausen Constant: No

Armstrong Number: No

Kaprekar Number: No

Catalan Number: No

Vampire Number: No

Taxicab Number: No

Super Prime: No

Friedman Number: No

Fermat Number: No

Cullen Number: No

OEIS Sequences

T(n,k)=Number of length n+4 0..k arrays with some disjoint pairs in every consecutive five terms having the same sum. A247927

Numbers k such that A361338(k) = 10. A361349

a(n) = M(n) + m(n) for n >= 2, where M(n) = max{ a(i) + a(n-i): i = 1..n-1 }, m(n) = min{ a(i) + a(n-i): i = 1..n-1 }. A22905

[ n(n-1)(n-2)(n-3)/17 ]. A11927

Number of length n+4 0..6 arrays with some disjoint pairs in every consecutive five terms having the same sum. A247925

Number of length 2+4 0..n arrays with some disjoint pairs in every consecutive five terms having the same sum. A247929

Number of n X n binary arrays with all ones connected only in a 0001-1101-0111 pattern in any orientation. A147255

The n X n X n dots problem: minimal number of straight lines (connected at their endpoints) required to pass through n³ dots arranged in an n X n X n grid, without exiting from the box [0, n] X [0, n] X [0, n]. A225227

The 3 X 3 X ... X 3 dots problem (3, n times): minimal number of straight lines (connected at their endpoints) required to pass through 3ⁿ dots arranged in a 3 X 3 X ... X 3 grid. A261547

a(n) = 4·n⁴ + 8·n³ - 4·n - 1 = (2·n² - 1)*(2·n² + 4·n + 1). A57769