Properties of the Number 41973

Forty-One Thousand Nine Hundred Seventy-Three

Basics

Value: 41972 → 41973 → 41974

Parity: odd

Prime: No

Previous Prime: 41969

Next Prime: 41981

Digit Sum: 24

Digital Root: 6

Palindrome: No

Factorization: 3 × 17 × 823

Divisors: 1, 3, 17, 51, 823, 2469, 13991, 41973

Polygonal

Triangular: No

Square: No

Pentagonal: No

Hexagonal: No

Heptagonal: No

Tetrahedral: No

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Representations

Binary: 1010001111110101

Octal: 121765

Duodecimal: 20359

Hexadecimal: a3f5

Square: 1761732729

Square Root: 204.87313147409057

Classification

Fibonacci: No

Bell Number: No

Factorial Number: No

Regular Number: No

Perfect Number: No

Special

Kaprekar Constant: No

Munchausen Constant: No

Armstrong Number: No

Kaprekar Number: No

Catalan Number: No

Vampire Number: No

Taxicab Number: No

Super Prime: No

Friedman Number: No

Fermat Number: No

Cullen Number: No

OEIS Sequences

Triangle R, read by rows, such that R³ transforms column k of R³ into column k+1 of R³, so that column k of R³ equals column 0 of R^3·k+3, where R³ denotes the matrix cube of R. A113389

Number T(n,k) of endofunctions on [n] such that at least one preimage with cardinality k exists and, if j is the largest value with a nonempty preimage, the preimage cardinality of i is >=k for all i<=j and equal to k for at least one i<=j; triangle T(n,k), n>=0, 0<=k<=n, read by rows. A245733

Triangle, read by rows, given by the product R^-2·Q³ = Q^-1·P² using triangular matrices P=A113370, Q=A113381, R=A113389. A114151

Triangle, read by rows, equal to the matrix cube of A113370. A113378

Number of asymmetric mobiles (circular rooted trees) with n nodes and 3 leaves. A55364

Column 0 of triangle A113378, also equals column 0 of A113389. A113379

Location of record values in A080577; also partial sums of A006128 plus 1. A124920

a(n) is the difference by which nⁿ overestimates the value of (1/2) ∑_k>=0 kⁿ/2^k. A133286

a(n) = (2·n³ + 5·n² - 13·n)/2. A162262

Triangle P, read by rows, such that P³ transforms column k of P into column k+1 of P, so that column k of P equals column 0 of P^3·k+1, where P³ denotes the matrix cube of P. A113370