Properties of the Number 31841

Thirty-One Thousand Eight Hundred Forty-One

Basics

Value: 31840 → 31841 → 31842

Parity: odd

Prime: No

Previous Prime: 31817

Next Prime: 31847

Digit Sum: 17

Digital Root: 8

Palindrome: No

Factorization: 17 × 1873

Divisors: 1, 17, 1873, 31841

Polygonal

Triangular: No

Square: No

Pentagonal: No

Hexagonal: No

Heptagonal: No

Tetrahedral: No

Today's Target

2196 Try Today's Challenge

Representations

Binary: 111110001100001

Octal: 76141

Duodecimal: 16515

Hexadecimal: 7c61

Square: 1013849281

Square Root: 178.44046626256053

Classification

Fibonacci: No

Bell Number: No

Factorial Number: No

Regular Number: No

Perfect Number: No

Special

Kaprekar Constant: No

Munchausen Constant: No

Armstrong Number: No

Kaprekar Number: No

Catalan Number: No

Vampire Number: No

Taxicab Number: No

Super Prime: No

Friedman Number: No

Fermat Number: No

Cullen Number: No

OEIS Sequences

Number of subsets of {1..n} containing no products of two or more distinct elements. A326117

Number of vertices formed in a square by straight line segments when connecting the four corner vertices to the points dividing the sides into n equal parts. A355949

Structured disdyakis dodecahedral numbers (vertex structure 7). A100162

Coefficients of power series generated by the continued fraction-like form: A(x) = 1/(1 - x/sqrt(1 - 4x/cube-root(1 - 9x/4th-root(1 - 16x/5th-root(1 - 25x/... /n-th-root(1 - (n²)x/...)))))), where n-th-root(z)=z^1/n. A75820

Irregular triangle read by rows: T(n,k) is the number of n X n tic-tac-toe positions (up to rotation and reflection) with k tokens (i.e., after k plays) which allow a winning strategy for O (n > 0, 0 <= k <= n²). A317574

Number of n X 6 0..1 arrays with rows and antidiagonals unimodal and columns nondecreasing. A224144

a(n) = ∑_{k=0..floor(n/3)} binomial(k+1,3·n-9·k+1). A392675

T(n,k) = Number of n X k 0..1 arrays with rows and antidiagonals unimodal and columns nondecreasing. A224146

G.f.: A(x) = F(0,x) where F(0,x) = 1/(1 - x·F(1,x)), F(1,x) = 1/(1 - 4·x*F(2,x)²)^1/2, F(2,x) = 1/(1 - 9·x/F(3,x)³)^1/3, F(3,x) = 1/(1 - 16·x/F(4,x)⁴)^1/4, ..., so that F(n,x) = 1/(1 - (n+1)²*x·F(n+1,x)ⁿ⁺¹)^1/(n+1) for n>=0. A243195

Numbers k such that the period of the continued fraction for sqrt(k) contains exactly 73 ones. A31841