Properties of the Number 23829

Twenty-Three Thousand Eight Hundred Twenty-Nine

Basics

Value: 23828 → 23829 → 23830

Parity: odd

Prime: No

Previous Prime: 23827

Next Prime: 23831

Digit Sum: 24

Digital Root: 6

Palindrome: No

Factorization: 3 × 13 ² × 47

Divisors: 1, 3, 13, 39, 47, 141, 169, 507, 611, 1833

Polygonal

Triangular: No

Square: No

Pentagonal: No

Hexagonal: No

Heptagonal: No

Tetrahedral: No

Today's Target

4823 Try Today's Challenge

Representations

Binary: 101110100010101

Octal: 56425

Duodecimal: 11959

Hexadecimal: 5d15

Square: 567821241

Square Root: 154.36644713149292

Classification

Fibonacci: No

Bell Number: No

Factorial Number: No

Regular Number: No

Perfect Number: No

Special

Kaprekar Constant: No

Munchausen Constant: No

Armstrong Number: No

Kaprekar Number: No

Catalan Number: No

Vampire Number: No

Taxicab Number: No

Super Prime: No

Friedman Number: No

Fermat Number: No

Cullen Number: No

OEIS Sequences

a(n) = (5·n² + 1)*n² / 6. A8354

a(n) = a(n - 1) - 2·a(n - 2) + a(n - 3) - 2·a(n - 4) + a(n - 5). A122582

Number of self-avoiding walks of length n on square lattice such that at each point the angle turns 90 degrees (the first turn is assumed to be to the left - otherwise the number must be doubled). A189722

Coefficients of modular function g₃(τ). A3297

Define the generalized Pisot sequence T(a(0),a(1)) by: a(n+2) is the greatest integer such that a(n+2)/a(n+1) < a(n+1)/a(n). This is T(3,5). A18917

a(n) = 1 + n*(n+1)*(n²-n+12)/12. A136396

a(n)= ∑_i=7..n+6 A000931(i). A167385

Triangle read by rows: T(n,k) is the number of weighted lattice paths B(n) having k HH's. B(n) is the set of lattice paths of weight n that start in (0,0), end on the horizontal axis and never go below this axis, whose steps are of the following four kinds: a (1,0)-step h of weight 1; a (1,0)-step H of weight 2; a (1,1)-step u of weight 2; a (1,-1)-step d of weight 1. The weight of a path is the sum of the weights of its steps. A246183

Composite terms in A270951. A351337

[ Sum{(sqrt(j+1)-sqrt(i+1))³} ], 1 <= i < j <= n. A25223